110A - Nearly Lucky Number - CodeForces Solution

implementation *800

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Python Code: 

s1 = input()
l = list(s1)
count_4 = l.count('4')
count_7 = l.count('7')
if((count_4+count_7) == 4 or (count_4+count_7) == 7):
    print('YES')
else:
    print("NO")


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